Discussion
Let p = 3q+1 and
q = 2r. Then 
*This question is included in Nova Press: Set K - Equations, question #4
| (A) | 32r-1 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 02/04/2013 17:43
Something is measing!
Posted: 02/04/2013 19:32
Andres, we apologize that there seems to be an issue with rendering certain images in some problems. Here is the complete problem:
Let p = 3^(q+1) and q=2r. Then p/3^2 = ?
Let p = 3^(q+1) and q=2r. Then p/3^2 = ?
Posted: 02/04/2013 20:06
Here are the choices:
A. 3^(2r-1)
B. 3^2r
C. 3
D. r
E. 3^(2r+1)
A. 3^(2r-1)
B. 3^2r
C. 3
D. r
E. 3^(2r+1)