Discussion

If the integer x is divisible by 3 but not by 2, then which one of the following expressions is NEVER an integer?
 

(A)

x + 1 2

(B)...
(C)...
(D)...
(E)...
(F)...
*This question is included in Nova Math - Problem Set A: Substitution, question #12

The solution is

Posted: 07/24/2012 18:53
For choice b, when you sub x=3 3/7 is not an integer... How do you know to sub another number? How come you don't try all numbers for all choices?
Posted: 07/13/2015 07:24
Reply: because the question says "NEVER"an integer. So you look for other possibilities. For questions with "never", "cannot be" process of elimination works quite good.
Good luck with your exam!
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Contributor
Posted: 07/25/2012 01:58
For this kind of questions, we kind of have to pick numbers that prove the question wrong (in this case: to prove that it can be an integer, so we can eliminate it).
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Contributor
Posted: 07/25/2012 02:00
Continued. For example: in choice A, the denominator is 2, so pick an x that is a multiple of 3, and an x that will make the numerator even, so that choice A would be an integer.
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Contributor
Posted: 07/25/2012 02:03
Continued. For B, pick an x that is a multiple of 3, and also that is a multiple of 7 (since the denominator is 7), in order to make the value whole. That means x = 21. And so on. In conclusion, we have to think what numbers to pick, they are not random, but ones that would help us eliminate choices.
Posted: 08/22/2012 12:33
Choice B would also be an alternate answer. If X had a value of 9 (which is divisible by 3 but not by 2) then x/7 would also not be an integer. The problem says that it can NEVER be an integer. Isn't answer B also a possible solution?
Posted: 08/22/2012 12:44
Andrew, no. If it is an integer even once, then it is not an answer
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Posted: 08/24/2013 00:07
If x is 48, for example, it is evenly divisible by 24.
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Admin
Posted: 08/24/2013 02:45
Hi A H,

If x = 48, then it is divisible by 2: 48/2 = 24.

But this is not allowed by the conditions of the problem: x is divisible by 3 but NOT by 2.

Nova Pres

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