Discussion
| (A) | 24x |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 07/11/2012 16:28
Can someone help me on this?
Posted: 07/18/2012 22:25
Hi Stacy. When an exponent is raised to another power, you simply multiply the "powers". In this case, 4 is raised to the power of x, then raised again to the power of 2. You simply multiply x by 2. So, we have 4^2x. But we don't have that as a choice. However, we know that 4 is 2^2 (2 squared, or 2 raised to the power of 2), so we can write the expression as (2^2)^2x.
So, again we can multiply the powers, making it: 2 raised to the power of 2⋄2x, or 2^4x, which is choice A.
So, again we can multiply the powers, making it: 2 raised to the power of 2⋄2x, or 2^4x, which is choice A.
Posted: 08/17/2016 12:22
I don't understand why the square doesn't apply to the coefficient as well. I came to the answer 16^(2x) or even 2^(8x)
Posted: 08/17/2016 14:41
Hi Nye,
We can use only the existing rules for manipulating exponents. You are tacitly using the rule (ab)^n = (a^n)(b^n).
But the x in the problem is not in the same position as the b in this rule, so this rule cannot be used. That is, we do not have the following:
(4x)^2 = (4^2)(x^2) = 16x^2
Nova Press
We can use only the existing rules for manipulating exponents. You are tacitly using the rule (ab)^n = (a^n)(b^n).
But the x in the problem is not in the same position as the b in this rule, so this rule cannot be used. That is, we do not have the following:
(4x)^2 = (4^2)(x^2) = 16x^2
Nova Press