## Discussion

If 3*x* + 9 = 15, then *x* + 2 =

(A) | 2 |

(B) | ... |

(C) | ... |

(D) | ... |

(E) | ... |

(F) | ... |

The solution is

Posted: 12/28/2011 07:39

How is the answer not 2 X+3=5 x is definitely 2.

Matt, you are right that x is 2; however the question asks for x+2, so the answer is 4 (C). You have to be careful in the test because sometimes the question writer is sneaky like that.

Posted: 01/03/2012 14:08

How do you get 4 if you divide 9 by3 wouldn't the answer be 3?

Joceline, dividing both sides of the equation by 3 gives you x + 3 = 5. We are solving for x, which is 2. then x + 2 = 4.

Posted: 01/29/2012 17:00

Where does the one come from

Camerin, I would say: "From heaven" or "Outside the Matrix" but that's me be being funny, since I am not sure which 'one' you refer to.

The question however requires you to first solve:

3x + 9 = 15

Subtract 9 from both sides

3x = 6

Divide both sides by 3

1x = 2

x = 2

This make the question

If x = 2 then x + 2 = 2 + 2 = 4

Another way would be;

3x + 9 = 15

Since each factor is a multiple of three, we divide each factor by 3

1x + 3 = 5

Subtract 3 from both sides

1x = 2

x = 2

x + 2 = 2 + 2 = 4

The only 'one' we have is in 1x which is the coefficient of variable x and though we know each variable has a coefficient we tend to omit it when it's equal to 1 since anything times 1 remain the same value.

Niels

The question however requires you to first solve:

3x + 9 = 15

Subtract 9 from both sides

3x = 6

Divide both sides by 3

1x = 2

x = 2

This make the question

If x = 2 then x + 2 = 2 + 2 = 4

Another way would be;

3x + 9 = 15

Since each factor is a multiple of three, we divide each factor by 3

1x + 3 = 5

Subtract 3 from both sides

1x = 2

x = 2

x + 2 = 2 + 2 = 4

The only 'one' we have is in 1x which is the coefficient of variable x and though we know each variable has a coefficient we tend to omit it when it's equal to 1 since anything times 1 remain the same value.

Niels

Posted: 09/19/2012 00:37

Do u have any other way to do that

Walid,

3x + 9 = 15, to start;

3 (x+3) = 15, by factoring out 3 on the left side;

x + 3 = 5, after dividing by 3 on both sides;

x + 2 = 4, after subtracting by 1 on both sides.

3x + 9 = 15, to start;

3 (x+3) = 15, by factoring out 3 on the left side;

x + 3 = 5, after dividing by 3 on both sides;

x + 2 = 4, after subtracting by 1 on both sides.

Posted: 12/04/2012 15:45

The answer is (C).

Posted: 10/13/2014 12:22

Reply: no it's noooooot

Posted: 05/05/2015 18:12

Test post

Posted: 06/08/2015 07:04

Reply: yeah