Discussion
If a = 3b, b2 = 2c, 9c = d, then 
*This question is included in Nova Press: Problem Solving Diagnostic Test, question #2
| (A) | 1/2 |
| (B) | ... |
| (C) | ... |
| (D) | ... |
| (E) | ... |
| (F) | ... |
The solution is
Posted: 11/30/2011 19:06
I don't get this because the b confused me
Posted: 12/01/2011 15:12
Here's a step by step explanation for Q2.
Posted: 01/02/2012 07:21
I am horribly confused by this exercise. I see the step by step, but not understanding how the solution is derived
Posted: 01/03/2012 22:20
Ramon, thanks for asking. The key for this kind of problem (fractions and ratios) is to express the denominator and numerator using a common variable, so that we can cancel the common variable and get a numerical answer (which is what the choices are). Since we are given hints that a and both can be expressed in c, we should do the substitutions to express a and d in terms of c. That's what the step by step video creator was trying to do. I hope this helps and don't hesitate to ask again if you are still confused.
Posted: 08/03/2013 08:08
Thank you very much!
Posted: 04/21/2012 22:38
Great explanation:) it helped me understand it!
Posted: 11/13/2013 04:44
glad to meet you